20-2400x^2=0-

Solution for 20-2400x^2=0- equation:

20-2400x^2=0-

We move all terms to the left:

20-2400x^2-(0-)=0

We add all the numbers together, and all the variables

-2400x^2+20-0=0

We add all the numbers together, and all the variables

-2400x^2+20=0

a = -2400; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·(-2400)·20
Δ = 192000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192000}=\sqrt{6400*30}=\sqrt{6400}*\sqrt{30}=80\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{30}}{2*-2400}=\frac{0-80\sqrt{30}}{-4800}
=-\frac{80\sqrt{30}}{-4800}
=-\frac{\sqrt{30}}{-60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{30}}{2*-2400}=\frac{0+80\sqrt{30}}{-4800}
=\frac{80\sqrt{30}}{-4800}
=\frac{\sqrt{30}}{-60}
$